12(-7+5b)=-12(1-10b)+12b

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Solution for 12(-7+5b)=-12(1-10b)+12b equation: 



12(-7+5b)=-12(1-10b)+12b

We move all terms to the left:

12(-7+5b)-(-12(1-10b)+12b)=0

We add all the numbers together, and all the variables

12(5b-7)-(-12(-10b+1)+12b)=0

We multiply parentheses

60b-(-12(-10b+1)+12b)-84=0



We calculate terms in parentheses: -(-12(-10b+1)+12b), so:

-12(-10b+1)+12b

We add all the numbers together, and all the variables

12b-12(-10b+1)

We multiply parentheses

12b+120b-12

We add all the numbers together, and all the variables

132b-12

Back to the equation:

-(132b-12)



We get rid of parentheses

60b-132b+12-84=0

We add all the numbers together, and all the variables

-72b-72=0

We move all terms containing b to the left, all other terms to the right

-72b=72

b=72/-72

b=-1

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