11y-8=4(3y-3)-y+4

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Solution for 11y-8=4(3y-3)-y+4 equation: 



11y-8=4(3y-3)-y+4

We move all terms to the left:

11y-8-(4(3y-3)-y+4)=0



We calculate terms in parentheses: -(4(3y-3)-y+4), so:

4(3y-3)-y+4

We add all the numbers together, and all the variables

-1y+4(3y-3)+4

We multiply parentheses

-1y+12y-12+4

We add all the numbers together, and all the variables

11y-8

Back to the equation:

-(11y-8)



We get rid of parentheses

11y-11y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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