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11x^2=7+5x
We move all terms to the left:
11x^2-(7+5x)=0
We add all the numbers together, and all the variables
11x^2-(5x+7)=0
We get rid of parentheses
11x^2-5x-7=0
a = 11; b = -5; c = -7;
Δ = b2-4ac
Δ = -52-4·11·(-7)
Δ = 333
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{333}=\sqrt{9*37}=\sqrt{9}*\sqrt{37}=3\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3\sqrt{37}}{2*11}=\frac{5-3\sqrt{37}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3\sqrt{37}}{2*11}=\frac{5+3\sqrt{37}}{22} $
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