11x2+-8x+8=0

Solution for 11x2+-8x+8=0 equation:

11x^2+-8x+8=0

We add all the numbers together, and all the variables

11x^2-8x=0

a = 11; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·11·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*11}=\frac{0}{22}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*11}=\frac{16}{22}
=8/11
$