11x/1x=336+4x

Solution for 11x/1x=336+4x equation:

11x/1x=336+4x

We move all terms to the left:

11x/1x-(336+4x)=0


Domain of the equation: 1x!=0

x∈R


We add all the numbers together, and all the variables

11x/1x-(4x+336)=0

We get rid of parentheses

11x/1x-4x-336=0

We multiply all the terms by the denominator


11x-4x*1x-336*1x=0

Wy multiply elements

-4x^2+11x-336x=0

We add all the numbers together, and all the variables

-4x^2-325x=0

a = -4; b = -325; c = 0;
Δ = b2-4ac
Δ = -3252-4·(-4)·0
Δ = 105625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{105625}=325$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-325)-325}{2*-4}=\frac{0}{-8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-325)+325}{2*-4}=\frac{650}{-8}
=-81+1/4
$