11x-4y=8;y=5x/2-2

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2x+y=8
x+3y=14

Solution for 11x-4y=8;y=5x/2-2 system of equations: 


  • /| 11*x-(4*y)-8 = 0| y-((5*x)/2)+2 = 0
  • We try to solve the equation: 11*x-(4*y)-8 = 0
  • 11*x-4*y-8 = 0 // - 11*x-8
  • -4*y = -(11*x-8) // : -4
  • y = (-(11*x-8))/(-4)
  • y = (8-(11*x))/(-4)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (8-(11*x))/(-4)-((5*x)/2)+2 = 0| y = (8-(11*x))/(-4)
  • (8-11*x)/(-4)+(-5*x)/2+2 = 0
  • 1/4*x-2+2 = 0
  • 1/4*x = 0
  • 1/4*x = 0 // : 1/4
  • x = 0
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (8-(11*x))/(-4): 
  • y = (8-(0*11))/(-4)
  • y = (0+8)/(-4)
  • y = 8/(-4)
  • y = -2
  • We get a system of equations:
  • /| y = -2| x = 0

 

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