11x-2(3-2x)=5(x-4)-6

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Solution for 11x-2(3-2x)=5(x-4)-6 equation: 



11x-2(3-2x)=5(x-4)-6

We move all terms to the left:

11x-2(3-2x)-(5(x-4)-6)=0

We add all the numbers together, and all the variables

11x-2(-2x+3)-(5(x-4)-6)=0

We multiply parentheses

11x+4x-(5(x-4)-6)-6=0



We calculate terms in parentheses: -(5(x-4)-6), so:

5(x-4)-6

We multiply parentheses

5x-20-6

We add all the numbers together, and all the variables

5x-26

Back to the equation:

-(5x-26)



We add all the numbers together, and all the variables

15x-(5x-26)-6=0

We get rid of parentheses

15x-5x+26-6=0

We add all the numbers together, and all the variables

10x+20=0

We move all terms containing x to the left, all other terms to the right

10x=-20

x=-20/10

x=-2

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