11x-1=(4x+3)+(8)+(x)

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Solution for 11x-1=(4x+3)+(8)+(x) equation: 



11x-1=(4x+3)+(8)+(x)

We move all terms to the left:

11x-1-((4x+3)+(8)+(x))=0



We calculate terms in parentheses: -((4x+3)+8+x), so:

(4x+3)+8+x

determiningTheFunctionDomain
(4x+3)+x+8

We add all the numbers together, and all the variables

x+(4x+3)+8

We get rid of parentheses

x+4x+3+8

We add all the numbers together, and all the variables

5x+11

Back to the equation:

-(5x+11)



We get rid of parentheses

11x-5x-11-1=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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