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11x+6-5(x-1)=-5x(10x-5)+5
We move all terms to the left:
11x+6-5(x-1)-(-5x(10x-5)+5)=0
We multiply parentheses
11x-5x-(-5x(10x-5)+5)+5+6=0
We calculate terms in parentheses: -(-5x(10x-5)+5), so:We add all the numbers together, and all the variables
-5x(10x-5)+5
We multiply parentheses
-50x^2+25x+5
Back to the equation:
-(-50x^2+25x+5)
-(-50x^2+25x+5)+6x+11=0
We get rid of parentheses
50x^2-25x+6x-5+11=0
We add all the numbers together, and all the variables
50x^2-19x+6=0
a = 50; b = -19; c = +6;
Δ = b2-4ac
Δ = -192-4·50·6
Δ = -839
Delta is less than zero, so there is no solution for the equation
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