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11x+15=2(2x+3)+7x+9
We move all terms to the left:
11x+15-(2(2x+3)+7x+9)=0
We calculate terms in parentheses: -(2(2x+3)+7x+9), so:We get rid of parentheses
2(2x+3)+7x+9
We add all the numbers together, and all the variables
7x+2(2x+3)+9
We multiply parentheses
7x+4x+6+9
We add all the numbers together, and all the variables
11x+15
Back to the equation:
-(11x+15)
11x-11x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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