11u2+13u+2=0

Solution for 11u2+13u+2=0 equation:

11u^2+13u+2=0

a = 11; b = 13; c = +2;
Δ = b2-4ac
Δ = 132-4·11·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-9}{2*11}=\frac{-22}{22}
=-1
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+9}{2*11}=\frac{-4}{22}
=-2/11
$