11r-4(r+3)=4(3r-5)-27

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Solution for 11r-4(r+3)=4(3r-5)-27 equation: 



11r-4(r+3)=4(3r-5)-27

We move all terms to the left:

11r-4(r+3)-(4(3r-5)-27)=0

We multiply parentheses

11r-4r-(4(3r-5)-27)-12=0



We calculate terms in parentheses: -(4(3r-5)-27), so:

4(3r-5)-27

We multiply parentheses

12r-20-27

We add all the numbers together, and all the variables

12r-47

Back to the equation:

-(12r-47)



We add all the numbers together, and all the variables

7r-(12r-47)-12=0

We get rid of parentheses

7r-12r+47-12=0

We add all the numbers together, and all the variables

-5r+35=0

We move all terms containing r to the left, all other terms to the right

-5r=-35

r=-35/-5

r=+7

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