11r-2(r+5)=5(4r-5)-18

Solution for 11r-2(r+5)=5(4r-5)-18 equation:

11r-2(r+5)=5(4r-5)-18

We move all terms to the left:

11r-2(r+5)-(5(4r-5)-18)=0

We multiply parentheses

11r-2r-(5(4r-5)-18)-10=0


We calculate terms in parentheses: -(5(4r-5)-18), so:

5(4r-5)-18

We multiply parentheses

20r-25-18

We add all the numbers together, and all the variables

20r-43

Back to the equation:

-(20r-43)


We add all the numbers together, and all the variables

9r-(20r-43)-10=0

We get rid of parentheses

9r-20r+43-10=0

We add all the numbers together, and all the variables

-11r+33=0

We move all terms containing r to the left, all other terms to the right

-11r=-33

r=-33/-11

r=+3