11n-5=1+6(n+2)

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Solution for 11n-5=1+6(n+2) equation: 



11n-5=1+6(n+2)

We move all terms to the left:

11n-5-(1+6(n+2))=0



We calculate terms in parentheses: -(1+6(n+2)), so:

1+6(n+2)

determiningTheFunctionDomain
6(n+2)+1

We multiply parentheses

6n+12+1

We add all the numbers together, and all the variables

6n+13

Back to the equation:

-(6n+13)



We get rid of parentheses

11n-6n-13-5=0

We add all the numbers together, and all the variables

5n-18=0

We move all terms containing n to the left, all other terms to the right

5n=18

n=18/5

n=3+3/5

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