11n+1+10=7(10+3n)-(2n+11)

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Solution for 11n+1+10=7(10+3n)-(2n+11) equation: 



11n+1+10=7(10+3n)-(2n+11)

We move all terms to the left:

11n+1+10-(7(10+3n)-(2n+11))=0

We add all the numbers together, and all the variables

11n-(7(3n+10)-(2n+11))+1+10=0

We add all the numbers together, and all the variables

11n-(7(3n+10)-(2n+11))+11=0



We calculate terms in parentheses: -(7(3n+10)-(2n+11)), so:

7(3n+10)-(2n+11)

We multiply parentheses

21n-(2n+11)+70

We get rid of parentheses

21n-2n-11+70

We add all the numbers together, and all the variables

19n+59

Back to the equation:

-(19n+59)



We get rid of parentheses

11n-19n-59+11=0

We add all the numbers together, and all the variables

-8n-48=0

We move all terms containing n to the left, all other terms to the right

-8n=48

n=48/-8

n=-6

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