11k-169=2(3-4k)-6k

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Solution for 11k-169=2(3-4k)-6k equation: 



11k-169=2(3-4k)-6k

We move all terms to the left:

11k-169-(2(3-4k)-6k)=0

We add all the numbers together, and all the variables

11k-(2(-4k+3)-6k)-169=0



We calculate terms in parentheses: -(2(-4k+3)-6k), so:

2(-4k+3)-6k

We add all the numbers together, and all the variables

-6k+2(-4k+3)

We multiply parentheses

-6k-8k+6

We add all the numbers together, and all the variables

-14k+6

Back to the equation:

-(-14k+6)



We get rid of parentheses

11k+14k-6-169=0

We add all the numbers together, and all the variables

25k-175=0

We move all terms containing k to the left, all other terms to the right

25k=175

k=175/25

k=7

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