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11c-5=3(2c-1)
We move all terms to the left:
11c-5-(3(2c-1))=0
We calculate terms in parentheses: -(3(2c-1)), so:We get rid of parentheses
3(2c-1)
We multiply parentheses
6c-3
Back to the equation:
-(6c-3)
11c-6c+3-5=0
We add all the numbers together, and all the variables
5c-2=0
We move all terms containing c to the left, all other terms to the right
5c=2
c=2/5
c=2/5
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