11c-2(c+1)=3(c-6)

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Solution for 11c-2(c+1)=3(c-6) equation: 



11c-2(c+1)=3(c-6)

We move all terms to the left:

11c-2(c+1)-(3(c-6))=0

We multiply parentheses

11c-2c-(3(c-6))-2=0



We calculate terms in parentheses: -(3(c-6)), so:

3(c-6)

We multiply parentheses

3c-18

Back to the equation:

-(3c-18)



We add all the numbers together, and all the variables

9c-(3c-18)-2=0

We get rid of parentheses

9c-3c+18-2=0

We add all the numbers together, and all the variables

6c+16=0

We move all terms containing c to the left, all other terms to the right

6c=-16

c=-16/6

c=-2+2/3

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