11=5(c-2)-(c-5)

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Solution for 11=5(c-2)-(c-5) equation: 



11=5(c-2)-(c-5)

We move all terms to the left:

11-(5(c-2)-(c-5))=0



We calculate terms in parentheses: -(5(c-2)-(c-5)), so:

5(c-2)-(c-5)

We multiply parentheses

5c-(c-5)-10

We get rid of parentheses

5c-c+5-10

We add all the numbers together, and all the variables

4c-5

Back to the equation:

-(4c-5)



We get rid of parentheses

-4c+5+11=0

We add all the numbers together, and all the variables

-4c+16=0

We move all terms containing c to the left, all other terms to the right

-4c=-16

c=-16/-4

c=+4

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