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11=2/3x-1x=15
We move all terms to the left:
11-(2/3x-1x)=0
Domain of the equation: 3x-1x)!=0We add all the numbers together, and all the variables
x∈R
-(-1x+2/3x)+11=0
We get rid of parentheses
1x-2/3x+11=0
We multiply all the terms by the denominator
1x*3x+11*3x-2=0
Wy multiply elements
3x^2+33x-2=0
a = 3; b = 33; c = -2;
Δ = b2-4ac
Δ = 332-4·3·(-2)
Δ = 1113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1113}}{2*3}=\frac{-33-\sqrt{1113}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1113}}{2*3}=\frac{-33+\sqrt{1113}}{6} $
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