11=(3/4)y+20

Solution for 11=(3/4)y+20 equation:

11=(3/4)y+20

We move all terms to the left:

11-((3/4)y+20)=0


Domain of the equation: 4)y+20)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-((+3/4)y+20)+11=0

We multiply all the terms by the denominator


-((+3+11*4)y+20)=0


We calculate terms in parentheses: -((+3+11*4)y+20), so:

(+3+11*4)y+20

We add all the numbers together, and all the variables

47y+20

Back to the equation:

-(47y+20)


We get rid of parentheses

-47y-20=0

We move all terms containing y to the left, all other terms to the right

-47y=20

y=20/-47

y=-20/47