11=(1/2)(7x-8)

Solution for 11=(1/2)(7x-8) equation:

11=(1/2)(7x-8)

We move all terms to the left:

11-((1/2)(7x-8))=0


Domain of the equation: 2)(7x-8))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/2)(7x-8))+11=0

We multiply parentheses ..

-((+7x^2+1/2*-8))+11=0

We multiply all the terms by the denominator


-((+7x^2+1+11*2*-8))=0


We calculate terms in parentheses: -((+7x^2+1+11*2*-8)), so:

(+7x^2+1+11*2*-8)

We get rid of parentheses

7x^2+1-8+11*2*

We add all the numbers together, and all the variables

7x^2

Back to the equation:

-(7x^2)


a = -7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-7)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-14}=0$