118=3(7-4b)+1

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Solution for 118=3(7-4b)+1 equation: 



118=3(7-4b)+1

We move all terms to the left:

118-(3(7-4b)+1)=0

We add all the numbers together, and all the variables

-(3(-4b+7)+1)+118=0



We calculate terms in parentheses: -(3(-4b+7)+1), so:

3(-4b+7)+1

We multiply parentheses

-12b+21+1

We add all the numbers together, and all the variables

-12b+22

Back to the equation:

-(-12b+22)



We get rid of parentheses

12b-22+118=0

We add all the numbers together, and all the variables

12b+96=0

We move all terms containing b to the left, all other terms to the right

12b=-96

b=-96/12

b=-8

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