118=2(3x+1)

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Solution for 118=2(3x+1) equation: 



118=2(3x+1)

We move all terms to the left:

118-(2(3x+1))=0



We calculate terms in parentheses: -(2(3x+1)), so:

2(3x+1)

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

-6x-2+118=0

We add all the numbers together, and all the variables

-6x+116=0

We move all terms containing x to the left, all other terms to the right

-6x=-116

x=-116/-6

x=19+1/3

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