117=1/2+h(10+3)

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Solution for 117=1/2+h(10+3) equation: 



117=1/2+h(10+3)

We move all terms to the left:

117-(1/2+h(10+3))=0



Domain of the equation: 2+h(10+3))!=0

We move all terms containing h to the left, all other terms to the right

h(10+3))!=-2

h∈R



We add all the numbers together, and all the variables

-(1/2+h13)+117=0

We get rid of parentheses

-h13+117-1/2=0

We multiply all the terms by the denominator


-h13*2-1+117*2=0

We add all the numbers together, and all the variables

-h13*2+233=0

Wy multiply elements

-2h^13+233=0

We do not support ehpression: h^13

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