116=(3x+3)+(2x)

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Solution for 116=(3x+3)+(2x) equation: 



116=(3x+3)+(2x)

We move all terms to the left:

116-((3x+3)+(2x))=0



We calculate terms in parentheses: -((3x+3)+2x), so:

(3x+3)+2x

We add all the numbers together, and all the variables

2x+(3x+3)

We get rid of parentheses

2x+3x+3

We add all the numbers together, and all the variables

5x+3

Back to the equation:

-(5x+3)



We get rid of parentheses

-5x-3+116=0

We add all the numbers together, and all the variables

-5x+113=0

We move all terms containing x to the left, all other terms to the right

-5x=-113

x=-113/-5

x=22+3/5

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