115=(x+5)+(2x+28)

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Solution for 115=(x+5)+(2x+28) equation: 



115=(x+5)+(2x+28)

We move all terms to the left:

115-((x+5)+(2x+28))=0



We calculate terms in parentheses: -((x+5)+(2x+28)), so:

(x+5)+(2x+28)

We get rid of parentheses

x+2x+5+28

We add all the numbers together, and all the variables

3x+33

Back to the equation:

-(3x+33)



We get rid of parentheses

-3x-33+115=0

We add all the numbers together, and all the variables

-3x+82=0

We move all terms containing x to the left, all other terms to the right

-3x=-82

x=-82/-3

x=27+1/3

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