115=(20+3x)+(20+2x)

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Solution for 115=(20+3x)+(20+2x) equation: 



115=(20+3x)+(20+2x)

We move all terms to the left:

115-((20+3x)+(20+2x))=0

We add all the numbers together, and all the variables

-((3x+20)+(2x+20))+115=0



We calculate terms in parentheses: -((3x+20)+(2x+20)), so:

(3x+20)+(2x+20)

We get rid of parentheses

3x+2x+20+20

We add all the numbers together, and all the variables

5x+40

Back to the equation:

-(5x+40)



We get rid of parentheses

-5x-40+115=0

We add all the numbers together, and all the variables

-5x+75=0

We move all terms containing x to the left, all other terms to the right

-5x=-75

x=-75/-5

x=+15

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