115=(2/3)p-25

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Solution for 115=(2/3)p-25 equation: 



115=(2/3)p-25

We move all terms to the left:

115-((2/3)p-25)=0



Domain of the equation: 3)p-25)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

-((+2/3)p-25)+115=0

We multiply all the terms by the denominator


-((+2+115*3)p-25)=0



We calculate terms in parentheses: -((+2+115*3)p-25), so:

(+2+115*3)p-25

We add all the numbers together, and all the variables

347p-25

Back to the equation:

-(347p-25)



We get rid of parentheses

-347p+25=0

We move all terms containing p to the left, all other terms to the right

-347p=-25

p=-25/-347

p=25/347

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