115(y+2)=3(4y+5)

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Solution for 115(y+2)=3(4y+5) equation: 



115(y+2)=3(4y+5)

We move all terms to the left:

115(y+2)-(3(4y+5))=0

We multiply parentheses

115y-(3(4y+5))+230=0



We calculate terms in parentheses: -(3(4y+5)), so:

3(4y+5)

We multiply parentheses

12y+15

Back to the equation:

-(12y+15)



We get rid of parentheses

115y-12y-15+230=0

We add all the numbers together, and all the variables

103y+215=0

We move all terms containing y to the left, all other terms to the right

103y=-215

y=-215/103

y=-2+9/103

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