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114+3=(1/3)p
We move all terms to the left:
114+3-((1/3)p)=0
Domain of the equation: 3)p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
-((+1/3)p)+114+3=0
We add all the numbers together, and all the variables
-((+1/3)p)+117=0
We multiply all the terms by the denominator
-((+1+117*3)p)=0
We calculate terms in parentheses: -((+1+117*3)p), so:p=0/-352
(+1+117*3)p
We add all the numbers together, and all the variables
352p
Back to the equation:
-(352p)
p=0
Równanie nie ma rozwiązania
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