112=7(1+3x)

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Solution for 112=7(1+3x) equation: 



112=7(1+3x)

We move all terms to the left:

112-(7(1+3x))=0

We add all the numbers together, and all the variables

-(7(3x+1))+112=0



We calculate terms in parentheses: -(7(3x+1)), so:

7(3x+1)

We multiply parentheses

21x+7

Back to the equation:

-(21x+7)



We get rid of parentheses

-21x-7+112=0

We add all the numbers together, and all the variables

-21x+105=0

We move all terms containing x to the left, all other terms to the right

-21x=-105

x=-105/-21

x=+5

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