112=(3y+3)+(4y-3)

Solution for 112=(3y+3)+(4y-3) equation:

Simplifying
112 = (3y + 3) + (4y + -3)

Reorder the terms:
112 = (3 + 3y) + (4y + -3)

Remove parenthesis around (3 + 3y)
112 = 3 + 3y + (4y + -3)

Reorder the terms:
112 = 3 + 3y + (-3 + 4y)

Remove parenthesis around (-3 + 4y)
112 = 3 + 3y + -3 + 4y

Reorder the terms:
112 = 3 + -3 + 3y + 4y

Combine like terms: 3 + -3 = 0
112 = 0 + 3y + 4y
112 = 3y + 4y

Combine like terms: 3y + 4y = 7y
112 = 7y

Solving
112 = 7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7y' to each side of the equation.
112 + -7y = 7y + -7y

Combine like terms: 7y + -7y = 0
112 + -7y = 0

Add '-112' to each side of the equation.
112 + -112 + -7y = 0 + -112

Combine like terms: 112 + -112 = 0
0 + -7y = 0 + -112
-7y = 0 + -112

Combine like terms: 0 + -112 = -112
-7y = -112

Divide each side by '-7'.
y = 16

Simplifying
y = 16