112+(4x)+(3x+12)=180

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Solution for 112+(4x)+(3x+12)=180 equation: 



112+(4x)+(3x+12)=180

We move all terms to the left:

112+(4x)+(3x+12)-(180)=0

We add all the numbers together, and all the variables

4x+(3x+12)-68=0

We get rid of parentheses

4x+3x+12-68=0

We add all the numbers together, and all the variables

7x-56=0

We move all terms containing x to the left, all other terms to the right

7x=56

x=56/7

x=8

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