110=(5+x)3x

Solution for 110=(5+x)3x equation:

110=(5+x)3x

We move all terms to the left:

110-((5+x)3x)=0

We add all the numbers together, and all the variables

-((x+5)3x)+110=0


We calculate terms in parentheses: -((x+5)3x), so:

(x+5)3x

We multiply parentheses

3x^2+15x

Back to the equation:

-(3x^2+15x)


We get rid of parentheses

-3x^2-15x+110=0

a = -3; b = -15; c = +110;
Δ = b2-4ac
Δ = -152-4·(-3)·110
Δ = 1545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{1545}}{2*-3}=\frac{15-\sqrt{1545}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{1545}}{2*-3}=\frac{15+\sqrt{1545}}{-6}
$