11/3c+12-c+1/c+4=c/3

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Solution for 11/3c+12-c+1/c+4=c/3 equation:


D( c )

c = 0

c = 0

c = 0

c in (-oo:0) U (0:+oo)

(11/3)*c-c+1/c+4+12 = c/3 // - c/3

(11/3)*c-c-(c/3)+1/c+4+12 = 0

7/3*c^1+1*c^-1+16*c^0 = 0

(7/3*c^2+16*c^1+1*c^0)/(c^1) = 0 // * c^2

c^1*(7/3*c^2+16*c^1+1*c^0) = 0

c^1

(7/3)*c^2+16*c+1 = 0

(7/3)*c^2+16*c+1 = 0

DELTA = 16^2-(1*4*(7/3))

DELTA = 740/3

DELTA > 0

c = ((740/3)^(1/2)-16)/(2*(7/3)) or c = (-(740/3)^(1/2)-16)/(2*(7/3))

c = 3/14*((740/3)^(1/2)-16) or c = -3/14*((740/3)^(1/2)+16)

c in { -3/14*((740/3)^(1/2)+16), 3/14*((740/3)^(1/2)-16)}

c in { -3/14*((740/3)^(1/2)+16), 3/14*((740/3)^(1/2)-16) }

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