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11/2x-6=1/4x+4
We move all terms to the left:
11/2x-6-(1/4x+4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x+4)!=0We get rid of parentheses
x∈R
11/2x-1/4x-4-6=0
We calculate fractions
44x/8x^2+(-2x)/8x^2-4-6=0
We add all the numbers together, and all the variables
44x/8x^2+(-2x)/8x^2-10=0
We multiply all the terms by the denominator
44x+(-2x)-10*8x^2=0
Wy multiply elements
-80x^2+44x+(-2x)=0
We get rid of parentheses
-80x^2+44x-2x=0
We add all the numbers together, and all the variables
-80x^2+42x=0
a = -80; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-80)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-80}=\frac{-84}{-160} =21/40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-80}=\frac{0}{-160} =0 $
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