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11/2x-1=5/x
We move all terms to the left:
11/2x-1-(5/x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
11/2x-(+5/x)-1=0
We get rid of parentheses
11/2x-5/x-1=0
We calculate fractions
11x/2x^2+(-10x)/2x^2-1=0
We multiply all the terms by the denominator
11x+(-10x)-1*2x^2=0
Wy multiply elements
-2x^2+11x+(-10x)=0
We get rid of parentheses
-2x^2+11x-10x=0
We add all the numbers together, and all the variables
-2x^2+x=0
a = -2; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-2)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-2}=\frac{-2}{-4} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-2}=\frac{0}{-4} =0 $
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