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11/2x-10=3x
We move all terms to the left:
11/2x-10-(3x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-3x+11/2x-10=0
We multiply all the terms by the denominator
-3x*2x-10*2x+11=0
Wy multiply elements
-6x^2-20x+11=0
a = -6; b = -20; c = +11;
Δ = b2-4ac
Δ = -202-4·(-6)·11
Δ = 664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{664}=\sqrt{4*166}=\sqrt{4}*\sqrt{166}=2\sqrt{166}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{166}}{2*-6}=\frac{20-2\sqrt{166}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{166}}{2*-6}=\frac{20+2\sqrt{166}}{-12} $
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