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11/2m-26/3m-108/6=-86/6
We move all terms to the left:
11/2m-26/3m-108/6-(-86/6)=0
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
Domain of the equation: 3m!=0We add all the numbers together, and all the variables
m!=0/3
m!=0
m∈R
11/2m-26/3m-18-(-86/6)=0
We get rid of parentheses
11/2m-26/3m-18+86/6=0
We calculate fractions
1548m^2/216m^2+1188m/216m^2+(-1872m)/216m^2-18=0
We multiply all the terms by the denominator
1548m^2+1188m+(-1872m)-18*216m^2=0
Wy multiply elements
1548m^2-3888m^2+1188m+(-1872m)=0
We get rid of parentheses
1548m^2-3888m^2+1188m-1872m=0
We add all the numbers together, and all the variables
-2340m^2-684m=0
a = -2340; b = -684; c = 0;
Δ = b2-4ac
Δ = -6842-4·(-2340)·0
Δ = 467856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{467856}=684$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-684)-684}{2*-2340}=\frac{0}{-4680} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-684)+684}{2*-2340}=\frac{1368}{-4680} =-19/65 $
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