11/2c=4/c-3

Solution for 11/2c=4/c-3 equation:

11/2c=4/c-3

We move all terms to the left:

11/2c-(4/c-3)=0


Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R



Domain of the equation: c-3)!=0

c∈R


We get rid of parentheses

11/2c-4/c+3=0

We calculate fractions


11c/2c^2+(-8c)/2c^2+3=0

We multiply all the terms by the denominator


11c+(-8c)+3*2c^2=0

Wy multiply elements

6c^2+11c+(-8c)=0

We get rid of parentheses

6c^2+11c-8c=0

We add all the numbers together, and all the variables

6c^2+3c=0

a = 6; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·6·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*6}=\frac{-6}{12}
=-1/2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*6}=\frac{0}{12}
=0
$