11/10u-2=9/8u

Solution for 11/10u-2=9/8u equation:

11/10u-2=9/8u

We move all terms to the left:

11/10u-2-(9/8u)=0


Domain of the equation: 10u!=0

u!=0/10

u!=0

u∈R



Domain of the equation: 8u)!=0

u!=0/1

u!=0

u∈R


We add all the numbers together, and all the variables

11/10u-(+9/8u)-2=0

We get rid of parentheses

11/10u-9/8u-2=0

We calculate fractions


88u/80u^2+(-90u)/80u^2-2=0

We multiply all the terms by the denominator


88u+(-90u)-2*80u^2=0

Wy multiply elements

-160u^2+88u+(-90u)=0

We get rid of parentheses

-160u^2+88u-90u=0

We add all the numbers together, and all the variables

-160u^2-2u=0

a = -160; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-160)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-160}=\frac{0}{-320}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-160}=\frac{4}{-320}
=-1/80
$