11/(b-1)=6/(b+1)

Solution for 11/(b-1)=6/(b+1) equation:

11/(b-1)=6/(b+1)

We move all terms to the left:

11/(b-1)-(6/(b+1))=0


Domain of the equation: (b-1)!=0

We move all terms containing b to the left, all other terms to the right

b!=1

b∈R



Domain of the equation: (b+1))!=0

b∈R


We calculate fractions


11b/((b-1)*(b+1)))+(-(6*(b-1))/((b-1)*(b+1)))=0


We calculate terms in parentheses: -(6*(b-1))/((b-1)*(b+1))), so:

6*(b-1))/((b-1)*(b+1))

We multiply all the terms by the denominator


6*(b-1))

We multiply parentheses

6b+

We add all the numbers together, and all the variables

6b

Back to the equation:

-(6b)


We add all the numbers together, and all the variables

-6b+11b/((b-1)*(b+1)))+(=0

We multiply all the terms by the denominator


-6b*((b-1)*(b+1)))+(+11b=0

We add all the numbers together, and all the variables

11b-6b*((b-1)*(b+1)))+(=0