11.x2=16x=64

Solution for 11.x2=16x=64 equation:

11.x^2=16x=64

We move all terms to the left:

11.x^2-(16x)=0

a = 11.; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·11.·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*11.}=\frac{0}{22}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*11.}=\frac{32}{22}
=1+5/11
$