11.2(2x-7)=6(x-5)+6

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Solution for 11.2(2x-7)=6(x-5)+6 equation: 



11.2(2x-7)=6(x-5)+6

We move all terms to the left:

11.2(2x-7)-(6(x-5)+6)=0

We multiply parentheses

22.4x-(6(x-5)+6)-78.4=0



We calculate terms in parentheses: -(6(x-5)+6), so:

6(x-5)+6

We multiply parentheses

6x-30+6

We add all the numbers together, and all the variables

6x-24

Back to the equation:

-(6x-24)



We get rid of parentheses

22.4x-6x+24-78.4=0

We add all the numbers together, and all the variables

16.4x-54.4=0

We move all terms containing x to the left, all other terms to the right

16.4x=54.4

x=54.4/16.4

x=3+4.33333333333/13.6666666667

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