11-6(x+2)=8-3(x+5)

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Solution for 11-6(x+2)=8-3(x+5) equation: 



11-6(x+2)=8-3(x+5)

We move all terms to the left:

11-6(x+2)-(8-3(x+5))=0

We multiply parentheses

-6x-(8-3(x+5))-12+11=0



We calculate terms in parentheses: -(8-3(x+5)), so:

8-3(x+5)

determiningTheFunctionDomain
-3(x+5)+8

We multiply parentheses

-3x-15+8

We add all the numbers together, and all the variables

-3x-7

Back to the equation:

-(-3x-7)



We add all the numbers together, and all the variables

-6x-(-3x-7)-1=0

We get rid of parentheses

-6x+3x+7-1=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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