11-5(3x2)+7x=1-8x

Solution for 11-5(3x2)+7x=1-8x equation:

11-5(3x^2)+7x=1-8x

We move all terms to the left:

11-5(3x^2)+7x-(1-8x)=0

We add all the numbers together, and all the variables

-53x^2+7x-(-8x+1)+11=0

We get rid of parentheses

-53x^2+7x+8x-1+11=0

We add all the numbers together, and all the variables

-53x^2+15x+10=0

a = -53; b = 15; c = +10;
Δ = b2-4ac
Δ = 152-4·(-53)·10
Δ = 2345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{2345}}{2*-53}=\frac{-15-\sqrt{2345}}{-106}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{2345}}{2*-53}=\frac{-15+\sqrt{2345}}{-106}
$