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11-5(2x-6)=41-2(5x+2)
We move all terms to the left:
11-5(2x-6)-(41-2(5x+2))=0
We multiply parentheses
-10x-(41-2(5x+2))+30+11=0
We calculate terms in parentheses: -(41-2(5x+2)), so:We add all the numbers together, and all the variables
41-2(5x+2)
determiningTheFunctionDomain -2(5x+2)+41
We multiply parentheses
-10x-4+41
We add all the numbers together, and all the variables
-10x+37
Back to the equation:
-(-10x+37)
-10x-(-10x+37)+41=0
We get rid of parentheses
-10x+10x-37+41=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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