11-3(x+1)=7(x-6)+2

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Solution for 11-3(x+1)=7(x-6)+2 equation: 



11-3(x+1)=7(x-6)+2

We move all terms to the left:

11-3(x+1)-(7(x-6)+2)=0

We multiply parentheses

-3x-(7(x-6)+2)-3+11=0



We calculate terms in parentheses: -(7(x-6)+2), so:

7(x-6)+2

We multiply parentheses

7x-42+2

We add all the numbers together, and all the variables

7x-40

Back to the equation:

-(7x-40)



We add all the numbers together, and all the variables

-3x-(7x-40)+8=0

We get rid of parentheses

-3x-7x+40+8=0

We add all the numbers together, and all the variables

-10x+48=0

We move all terms containing x to the left, all other terms to the right

-10x=-48

x=-48/-10

x=4+4/5

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