11-2(s-5)=7(s+2)

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Solution for 11-2(s-5)=7(s+2) equation: 



11-2(s-5)=7(s+2)

We move all terms to the left:

11-2(s-5)-(7(s+2))=0

We multiply parentheses

-2s-(7(s+2))+10+11=0



We calculate terms in parentheses: -(7(s+2)), so:

7(s+2)

We multiply parentheses

7s+14

Back to the equation:

-(7s+14)



We add all the numbers together, and all the variables

-2s-(7s+14)+21=0

We get rid of parentheses

-2s-7s-14+21=0

We add all the numbers together, and all the variables

-9s+7=0

We move all terms containing s to the left, all other terms to the right

-9s=-7

s=-7/-9

s=7/9

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